4cos^2(4x)+4sin^2(4x)=

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Solution for 4cos^2(4x)+4sin^2(4x)= equation: 


Simplifying
4cos2(4x) + 4sin2(4x) = 0

Remove parenthesis around (4x)
4cos2 * 4x + 4sin2(4x) = 0

Reorder the terms for easier multiplication:
4 * 4cos2 * x + 4sin2(4x) = 0

Multiply 4 * 4
16cos2 * x + 4sin2(4x) = 0

Multiply cos2 * x
16cos2x + 4sin2(4x) = 0

Remove parenthesis around (4x)
16cos2x + 4in2s * 4x = 0

Reorder the terms for easier multiplication:
16cos2x + 4 * 4in2s * x = 0

Multiply 4 * 4
16cos2x + 16in2s * x = 0

Multiply in2s * x
16cos2x + 16in2sx = 0

Solving
16cos2x + 16in2sx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-16in2sx' to each side of the equation.
16cos2x + 16in2sx + -16in2sx = 0 + -16in2sx

Combine like terms: 16in2sx + -16in2sx = 0
16cos2x + 0 = 0 + -16in2sx
16cos2x = 0 + -16in2sx
Remove the zero:
16cos2x = -16in2sx

Divide each side by '16os2x'.
c = -1in2o-1s-1

Simplifying
c = -1in2o-1s-1

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